Parse cli arguments in bash

Edit: Probably the cleanest looking while loop is still the 1st example on
https://mywiki.wooledge.org/BashFAQ/035

https://stackoverflow.com/questions/192249/how-do-i-parse-command-line-arguments-in-bash

#!/bin/bash

while [[ "$#" -gt 0 ]]; do
    case $1 in
        -t|--target) target="$2"; shift ;;
        -u|--uglify) uglify=1 ;;
        *) echo "Unknown parameter passed: $1"; exit 1 ;;
    esac
    shift
done

echo "Where to deploy: $target"
echo "Should uglify  : $uglify"

looks interesting. Or similar

while [ "$#" -gt 0 ]; do
    case "$1" in
        -n) name="$2"; shift 2;;
        -p) pidfile="$2"; shift 2;;
        -l) logfile="$2"; shift 2;;

        --name=*) name="${1#*=}"; shift 1;;
        --pidfile=*) pidfile="${1#*=}"; shift 1;;
        --logfile=*) logfile="${1#*=}"; shift 1;;
        --name|--pidfile|--logfile) echo "$1 requires an argument" >&2; exit 1;;
        
        -*) echo "unknown option: $1" >&2; exit 1;;
        *) handle_argument "$1"; shift 1;;
    esac
done
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